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# Math Problem

Math Problem

Question 1

Prices under offer (1)

Therefore, the price is £4.50 – £1.35 = £3.15

Therefore, the price is £1.29 – £0.387 = £0.903

Prices under offer (2)

• If 70% = 450 g

100% =?

• 100% = £1.29

70% =?

Prices under offer (3)

Buy one, get another one half price

One 450g pack = £4.50

Half of £4.50 = £2.25

So, two 450g packs cost = £4.50 + £2.25 = £6.75

Therefore,

If 900g = £6.75

Then, 100g =

Percentage decrease

£1.29 – £0.75 = £0.54

Comparison table

Question 2

1. 1 : 25 000

This means that 1 cm on the map represents 25 000 cm on the ground

Therefore, 18.4 cm represents:

18.4 cm x 25 000 cm = 460000 cm

This is equivalent to 460,000cm divided by 100,000cm = 4.6 km

• (i)

Distance = 8 km

Time = 2.5 hours

(ii) 1 km/h = 0.277778 m/s

Therefore, 0.277778 x 3.2 = 0.89 m/s

• (i)   180m – 60m = 120m

120m + 250m = 370m

370m – 150m = 220m

Highest height = 370m

Lowest height = 120m

(ii)  Number line

(iii)

• Naismith’s Rule

H = 140 m

D = 2.6 km or 2600 m

T = 520 + 0.23 + 104 = 624.23 minutes

Question 3

• Hay eating table of an overweight horse
•
• Graph
• First is to pinpoint where 6.5 kg of hay is on the vertical axis and draw a straight line to join the line of the plot and then check the value of ideal body-weight of the horse of the horizontal axis.
• (i) Charges

£65 = to shoe a horse

£20 = to trim an unshod horse hooves

£10 = travelling

Total charge = (2 x £20) + (3 x £65) + £10

Overall total = £40 + £195 + £10 = £245

(ii)  Assume x = the number of horses to shoe

y = the number to trim an unshod hooves

C = 65 x + 20 y + 10

Reference

Magyari-Sáska, Z. & Dombay, Ş. (2012). Determining minimum hiking time using DEM. Geographia Napocensis (Academia Romana – Filiala Cluj Colectivul de Geografie). Anul VI (2): 124–9. Retrieved 5 November 2014.